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已知tanα=3则3sinα^2-sinαcosα+2=?
人气:117 ℃ 时间:2020-02-05 12:42:17
解答
tanα=3
sinα/cosα=3
sin^2α/cos^2α=9
(1-cos^2α)/cos^2α=9
1/cos^2α-1=9
cos^2α = 1/10
3sinα^2-sinαcosα+2
= cos^2α(3tan^2α-tanα)+2
= 1/10*(3*3^2-3) + 2
= 12/5+2
= 22/5
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