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计算:(1)(√1/8-√32)-(1/√2+2√1/2);(2)(9/√27-√18)-(4√1/2-√12)
人气:356 ℃ 时间:2019-11-07 04:38:45
解答
(1)(√1/8-√32)-(1/√2+2√1/2)
=√2/4-4√2-√2/2-√2
=-21√2/4
(2)(9/√27-√18)-(4√1/2-√12)
=9/3√3-3√2-2√2+2√3
=3√3-5√2
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