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用克莱姆法则解线性方程组
x1+x2-2x3=-3
2x1+x2-x3=1
x1-x2+3x3=8
人气:455 ℃ 时间:2019-11-06 16:47:26
解答
D =
1 1 -2
2 1 -1
1 -1 3
= 1
D1 =
-3 1 -2
1 1 -1
8 -1 3
= 1
D2 =
1 -3 -2
2 1 -1
1 8 3
= 2
D3 =
1 1 -3
2 1 1
1 -1 8
= 3
所以 x1 = D1/D = 1
x2 = D2/D = 2
x3 = D3/D = 3
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