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﹙1/cos²80-3/cos²10﹚·1/cos20
人气:306 ℃ 时间:2020-06-26 20:11:13
解答
(1/cos^280-3/cos^210)*(1/cos20)=(1/cos^2(90-10)-3/cos^210)(1/cos20)=(1/sin^210-3/cos^210)*(1/cos20)=(cos^210-3sin^210)/(sin^210*cos^210)*(1/cos20)=(4cos^210-3)/(sin^210*cos^210)*(1/cos20)=(2cos20-1)/(...
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