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x^2-4x+m-1=0 怎么求根
人气:206 ℃ 时间:2020-06-21 15:28:45
解答
x^2 -4x + m-1= 0
x^2 -4x +4 + m -5 = 0
(x-2)^2 = 5-m
1)5-m < 0 :无解
2)5-m=0:x=2
3)5-m>0
x-2 = +- (5-m)^1/2
x1 = - (5-m)^1/2 +2
x2= (5-m)^1/2 +2
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