（1+tan2α）/（1-tanα）=2010=>{1+2tanα/[(1-tanα)^2]}/(1-tanα)=1-(tanα)^2+2tanα=2010(1+tanα)=>2009+(tanα)^2+2008tanα=0 (1)=>(1+tanα)=[tanα-(tanα)^2]/20091/cos2α+tan2α=(1+sin2α)/cos2α=(1...