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a^2b^2-1分之ab-2a^2b^2+a^3b^3 ab=-2
人气:294 ℃ 时间:2020-05-24 04:45:30
解答
a^2b^2-1分之ab-2a^2b^2+a^3b^3 ab=-2
=(ab-2a^2b^2+a^3b^3)/(a^2b^2-1)
=ab(1-2ab+a^2b^2)/(a^2b^2-1)
=ab(ab-1)^2/(ab-1)(ab+1)
=ab(ab-1)/(ab+1)
=-2*(-2-1)/(-2+1)
=-6
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