本题题意有二：若是y = log₂【x(3-x)】= ln【x(3-x)】/ln2= 【lnx + ln(3-x)】/ln2dy/dx = 1/(xln2) - 1/(3-x)ln2若 x = 1dy/dx|(x=1) = 1/ln2 - 1/2ln2 = 1/2ln2 （或 1/ln4）若是y = log(2x)【3-x】= ln(3-x...