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分式计算,
(1)s-2t/3s × 6s²/s+2t
(2)u-2v/u+2v - 2/u²-4v²
(3)2a/a+1 + 2/a+1
人气:367 ℃ 时间:2020-06-05 09:58:01
解答
(1)s-2t/3s×6s²/s+2t=(s-2t)*2s/(s+2t)
(2)u-2v/u+2v-2/u²-4v²=u-2v/u+2v -2/[(u-2v)(u+2v)]=[(u-2v)²-2]/[(u-2v)(u+2v)]
(3)2a/a+1+2/a+1=(2a+2)/(a+1)=2(a+1)/(a+1)=2
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