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数学
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Na2Sx+NaClO+NaOH=Na2SO4+NaCl+H2O
人气:164 ℃ 时间:2019-12-25 03:58:31
解答
· -2/x +1 +6 -1
Na2Sx + (3x+1)NaClO+NaOH=xNa2SO4+(3x+1)NaCl+H2O 可以把Sx看做整体
升6x+2 降2
接着按照Na、H、O的顺序配平
Na2Sx + (3x+1)NaClO+(2x-2)NaOH=xNa2SO4+(3x+1)NaCl+(x-1)H2O
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配平方程式:Na2Sx+NaClO+NaOH=Na2SO4+NaCl+H2O(注:x为S的角标)
Cl2+NaOH-NacL+NacLO+H2O
1)_Na2Sx+_NaClO+_NaOH=_Na2SO4+_NaCl+_H2O
Cl2+NaOH==NaCl+NaClO+H2O如何配平
(1)_Na2Sx+_NaClO+_NaOH=_Na2SO4+_NaCl+_H2O (2)_Cu2S+HNO3=_H2SO4+_NO+_Cu(NO3)2+___
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