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(3x²-2y²)(-2y²-3x²)+3(x²-y²)(x²+y²)
人气:102 ℃ 时间:2020-03-29 06:26:30
解答
(3x²-2y²)(-2y²-3x²)+3(x²-y²)(x²+y²)
= -(3x²-2y²)(3x²+2y²)+3(x²-y²)(x²+y²)
=-(9x⁴-4y⁴)+3(x⁴-y⁴)
=-9x⁴+4y⁴+3x⁴-3y⁴
=-6x⁴+y⁴
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