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3n(3n+3)(3n+6)(3n+9)+81的因式分解
人气:321 ℃ 时间:2020-05-08 19:38:26
解答
3n(3n+3)(3n+6)(3n+9)+81=(3n)^4+(3n)^3(3+6+9)+(3n)^2((6*9+3*6+3*9)+3n*(3*6*9)+81
=81n^4+486n^3+891n^2+486n+81
看来是我对因式分解出了点问题
3n(3n+3)(3n+6)(3n+9)+81=81{n(n+1)(n+2)(n+3)+1}
=81{(n^2+3n)(n^+3n+2)+1}=81(n^2+3n+1)^2
楼下是对的,现在成楼上的了
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