依题设,得 25^x=2000=25×80=80^y
则 25^(x-1)=80,80^(y-1)=25
则 [25^(x-1)]^(y-1)=25
即 25^[(x-1)(y-1)]=25
∴ (x-1)(y-1)=1 故 x+y-xy=0