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若cos(x-30°)=5/13,-60°小于x小于30°,则cosx=
人气:214 ℃ 时间:2020-06-03 20:50:52
解答
-60°-90°sin(x-30°)<0
sin(x-30°)
=-√[1-cos²(x-30°)]
=-√[1-(5/13)²]=-12/13
cosx
=cos[(x-30°)+30°]
=cos(x-30°)cos30°-sin(x-30°)sin30°
=5/13×√3/2-(-12/13)×1/2
=(5√3+12)/26
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