投入物体密度ρ物＝m/V=G/(gV)=4/(9.8x0.0006)=680(kg/m^3),而水的密度ρ水=1000kg/m^3,ρ物＜ρ水,所以,投入的物体漂浮在水上.F浮=G物=4N.按理说溢出的水是300g,根据F浮=ρ液gV排=G排液=0.3x10=3N,浮力应等于3N,问...