A于B互为相反数,B与C互为倒数,且C+根号2=0,化简A-1的绝对值+根号（A-2）的2次
如题
人气：482 ℃ 时间：2019-08-20 05:27:08
解答
A+B=0
BC=1
C+√2=0
C=-√2
B=-√2/2
A=√2/2
│A-1│+√[(A-2)^2]
=1-√2/2+(2-√2/2)
=3-√2
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