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若xy=2,求1/(4x^2)+1/(9y^2)的最值
人气:136 ℃ 时间:2020-04-10 17:45:47
解答
∵xy=2, ∴Y=2/X
1/(4x^2)+1/(9y^2)=1/4X²+1/(9(2/X)²)=1/4(1/X²+X²/9)
由a²+b²≥2ab得1/X²+X²/9≥ 2×(1/x )( x/3 ) ∴ 1/X²+X²/9≥6
1/(4x^2)+1/(9y^2)≥6/4
1/(4x^2)+1/(9y^2)的最小值是3/2
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