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把下列各式分解因式:
(1)4x3-31x+15;
(2)2a2b2+2a2c2+2b2c2-a4-b4-c4
(3)x5+x+1;
(4)x3+5x2+3x-9;
(5)2a4-a3-6a2-a+2.
人气:177 ℃ 时间:2020-05-08 09:35:10
解答
(1)4x3-31x+15=4x3-x-30x+15=x(2x+1)(2x-1)-15(2x-1)=(2x-1)(2x2+x-15)=(2x-1)(2x-5)(x+3);(2)2a2b2+2a2c2+2b2c2-a4-b4-c4=4a2b2-(a4+b4+c4+2a2b2-2a2c2-2b2c2)=(2ab)2-(a2+b2-c2)2=(2a...
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