1 =(2ab+a2+b2)(2ab-a2-b2)=-(a+b)2*(a-b)22：原式=（c2-a2-b2+2ab）(c2-a2-b2-2ab) =(c2-(a-b)2)(c2-(a+b)2)=(c+a-b)(c-a+b)(c-a-b)(c+a+b)3;原式=(1-(a2-1)(b2-1))(a+1)(a-1)(b+1)(b-1)...