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异分母分式加减法题目
(1) 3/(x-2)(x-1) - 1/x-2
(2) x/2-x - 4-x²/x²-4x+4
(3) 2/a²-1 + 1/a+1
人气:190 ℃ 时间:2020-03-26 10:39:48
解答
(1) 3/(X-2) (X-1) - 1/X-2 (2) x/2-x - 4-x²/x²-4x+4
=3/(X-2) (X-1) - X-1/ (X-2) (X-1) =X/2-X - (2+X)(2-X)/(X-2)(X-2)
=3-X+1/(X-2) (X-1) =X/2-X - 2+X/2-X
=4-X/(X-2) (X-1) =X-2-X/2-X
(3) 2/a²-1 + 1/a+1 =2/X-2
=2/(a+1)(a-1) + 1/a+1
=2/(a+1)(a-1) + a-1/(a+1)(a-1)
=2+a-1/(a+1)(a-1)
=3+a/a²-1
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