y=√(x²-2x+5)y'=1/[2√(x²-2x+5)]*(2x-2)=(x-1)/√(x²-2x+5)这是复合函数,可设u=x²-2x+5,y=√uu的导数u'=2x-2y的导数y'=1/(2√u)根据复合函数链式法则:y'=1/(2√u)*(2x-2)=1/(2√u)*2(x-1)=(x-...