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已知X-Y不等于0,X^2-X=3/4,Y^2-Y=3/4,求X^3+Y^3+X^2Y+XY^2的值
人气:251 ℃ 时间:2019-11-18 05:19:32
解答
当x^2-x=y^2-y时,x=-y+1
当x=-y+1时,x^3+y^3=x^2y+xy^2
=(-y+1)(1-2y+y^2)+y^3+(1-2y+y^2)y+(-y+1)y^2
=1-2y+y^2+y^3-y^3+y^2
=2y^2-2y+1
当y^2-y=3/4时,原式=2y^2-2y+1
=2(y^2-y)+1
=5/2
= =酷睿孩子
仅供参考.- -我的答案这样而已
噗噗噗= =但打下来不容易啊.
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