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数学
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求不定积分x ∫(1-x^2)/x根号下x dx
∫(1-x^2)/x*根号下x dx
人气:478 ℃ 时间:2020-03-21 18:56:07
解答
∫(1-x^2)/x^(3/2) dx
=∫[x^(-3/2) - x^(1/2)] dx
= -2x^(1/2) - (2/3)x^(3/2) + c
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