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求不定积分∫(arctanx)/(x^2(x^2+1))dx
人气:101 ℃ 时间:2020-04-11 02:45:56
解答
∫(arctanx)/(x^2(x^2+1))dx=∫(arctanx)/x^2dx-∫(arctanx)/(x^2+1)dx=∫(arctanx)d(1/x)-∫(arctanx)darctanx=arctanx/x-∫1/xdarctanx-1/2(arctanx)^2=arctanx/x-1/2(arctanx)^2-∫1/[x(x^2+1)]dx=arctanx/x-1/2(...
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