6V3W的灯泡L1和6V2W的灯泡串联后接入6V电路中,L1的实际电功率是多少L2以及总电功率
人气：218 ℃ 时间：2019-08-21 05:36:08
解答
根据R=U^2/P,R1=12欧姆,R2=18欧姆.串联后电阻30欧姆.接入6V电路,电流是I=U/R=6/30=0.2A.串联电路中I相同,根据P=I^2*R
P1=0.48W,P2=0.72W.
总功率=1.2W.
验算总功率：P=U^2/R=6*6/30=1.2W
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