题目应是：已知实数a,b满足（a+b)²=1,（a-b)²=5,a²+b²+ab的值(a+b)^2=1a^2+2ab+b^2=1(a-b)^2=5a^2-2ab+b^2=5两式相加2a^2+2b^2=6a^2+b^2=3两式相减4ab=-4ab=-1a^2+b^2+ab=3-1=2...