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分解因式 x²y-x²z+y²-y³
人气:473 ℃ 时间:2020-01-31 13:34:22
解答
x²y-x²z+y²z-y³
=x²(y-z)-y²(y-z)
=(x²-y²)(y-z)
=(x+y)(x-y)(y-z)
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