∫(x-1)/√(9-4x^2)dx
=∫ x/√(9-4x^2)dx - ∫ 1/√(9-4x^2)dx
= -1/8 *∫ 1/√(9-4x^2)d(9-4x^2) - 0.5*∫ 1/√[1-(2x/3)^2 ]d (2x/3)
= -1/4 *√(9-4x^2) - 0.5 *arcsin(2x/3) +C,C为常数