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求1/2x^2-1/4x+0.2x^3+0.25x-0.5x^2-1/5x^3+0.5x-1 其中x=12/13
人气:193 ℃ 时间:2019-11-10 08:22:15
解答
1/2x^2-1/4x+0.2x^3+0.25x-0.5x^2-1/5x^3+0.5x-1
=(1/2x^2-0.5x^2)+(0.25x-1/4x)+(0.2x^3-1/5x^3)+0.5x-1
=0.5x-1
=0.5*12/13-13/13
=-7/13再细点1/2x^2-1/4x+0.2x^3+0.25x-0.5x^2-1/5x^3+0.5x-1 =1/2x^2-0.5x^2+0.25x-1/4x+0.2x^3-1/5x^3+0.5x-1(把X次方相同的项放在一起,调整相关数及其符号的位置)=(1/2x^2-0.5x^2)+(0.25x-1/4x)+(0.2x^3-1/5x^3)+0.5x-1(全是加减法,两两合并计算)=(0.5x^2-0.5x^2)+(0.25x-0.25x)+(0.2x^3-0.2x^3)+0.5x-1(1/2=0.5;1/4=0.25;1/5=0.2)=0+0+0+0.5x-1=0.5*12/13-13/13=-7/13
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