f(x)=√3sinxcosx+cos²x=(√3/2)sin2x+(1+cos2x)/2-1/2=(√3/2)sin2x+(1/2)cos2x=sin2x*cos(π/6)+cos2x*sin(π/6)=sin(2x+π/6)(1)T=2π/2=π 增区间 2kπ-π/2≤2x+π/6≤2kπ+π/22kπ-2π/3≤2x≤2kπ+π/3...