定积分∫(上3下 -1)|x^2-2x|dx等于
定积分∫(上3下 -1)|x^2-2x|dx等于( )
A ,1 B,2 C ,3 D ,4
人气:187 ℃ 时间:2020-04-30 22:55:26
解答
∵∫│x^2-2x│dx=∫(x^2-2x)dx+∫(2x-x^2)dx+∫(x^2-2x)dx
=(x^3/3-x^2)│+(x^2-x^3/3)│+(x^3/3-x^2)│
=(1/3+1)+(4-8/3)+(9-9-8/3+4)
=4
∴应该选择答案D ,4.
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