已知(X-6)^2+根号2X+6Y+|3Y+2Z-X|=0,求根号X^2+(X-Y)^2的值?
【^2是平方2】 (2X-Y)(Y+2X)-(2Y+X)(2Y-X),其中X=1,Y=2,
人气:191 ℃ 时间:2019-10-23 11:17:38
解答
(X-6)^2+根号2X+6Y+|3Y+2Z-X|=0可得 x-6=0 2x+6y=0 3y+2z-x=0 解得x=6 y=2 z=0 所以X^2+(X-Y)^2=52
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