隐函数求导 一次全导,y'*e^y+xy'+y=0 => y'=-y/(e^y+x) 两边再取全导 y''*e^y+(y')^2*e^y+xy''+y'+y'=0 (e^y+x)*y''+e^y*(y')^2+2y'=0 x=0, y(0)=1, y'(0)=-e^(-1), e*y''(0)+e*e^(-2)+2[-e^(-1)]=0 ey''(0)=-e^...