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(3m+2n)^2-(2m+3n)^2
人气:149 ℃ 时间:2019-10-05 02:34:53
解答
(3m+2n)^2-(2m+3n)^2
=[(3m+2n)+(2m+3n)]×[(3m+2n)-(2m+3n)]
=(5m+5n)×(m-n)
=5×(m+n)(m-n)
=5m^2-5n^2
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2m+3n=3m-2n=3
3m+2n=16 2m+3n=-1
(3m+2n)²-(2m+3n)
已知a^2m=2,b^3n=3,求(a^3m)^2-(b^2n)^3的值
(2m*2n*-2)*2×3m*-3n*3
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