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求证 1/sin2x+1/cos2x-1/tan2x=2+tan2x
2为次数
人气:230 ℃ 时间:2020-04-14 13:07:41
解答
证明:
1/sin^2 x+1/cos^2 x-1/tan^2 x
=(sin^2 x+cos^2 x)/sin^2 x+(sin^2 x+cos^2 x)/cos^2 x - 1/tan^2 x
=1+1/tan^2 x+1+tan^2 x-1/tan^2 x
=2+tan^2 x
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