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已知x分之一减y分之一等于5,则代数式
(2x-11xy-2y)\(x-2xy-y)的值为
人气:111 ℃ 时间:2019-09-04 02:11:20
解答
1/x-1/y=5
y/(xy)-x/(xy)=5
y-x=5xy
x-y=-5xy
(2x-11xy-2y)/(x-2xy-y)
=[2(x-y)-11xy]/(x-y-2xy)
=[2(-5xy)-11xy]/(-5xy-2xy)
=(-21xy)/(-7xy)
=3
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