1/x-1-1/x+1-2/x的平方+1-4/x的四次方+1-8/x的八次方+1
=(x+1-x+1)/(x²-1)-2/(x²+1)-4/(x^4+1)-8/(x^8+1)
=(2x²+2-2x²+2)/(x^4-1)-4/(x^4+1)-8/(x^8+1)
=(4x^4+4-4x^4+4)/(x^8-1)-8/(x^8+1)
=(8x^4+8-8x^4+8)/(x^16-1)
=16/(x^16-1)