y1=arcsin(sinx)的定义域为R.值域为[-π/2,π/2]y2=arccos(cosx)的定义域为R.值域为[0,π]故(a)当x∈[2kπ,2kπ+π/2](第一象限)时,y1=x-2kπ,y2=x-2kπy1+y2=π/22x-4kπ=π/2x=2kπ+π/4 .(1)(b)当x∈[2kπ+π/2,2...