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计算:(x-y)^2/(x+y)÷(y-x)×1/(x-y)
(m^2-4n^2)/(3mn^3)×mn/(m+2n)
人气:406 ℃ 时间:2020-10-01 15:03:22
解答
原式=(x-y)^2/(x+y)×[-1/(x-y)]×1/(x-y)
=-(x-y)/(x+y)×1/(x-y)
=-1/(x+y)
原式=(m+2n)(m-2n)/(3mn^3)×mn/(m+2n)
=(m-2n)/(3n^2
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