原式=[(x-2)(x+2)-5]/(x+2)×[2(x+2)/(x-3)]=(x²-4-5)/(x+2)×[2(x+2)/(x-3)]=(x²-9)/(x+2)×[2(x+2)/(x-3)]=(x+3)(x-3)/(x+2)×[2(x+2)/(x-3)]=2(x+2)(x+3)(x-3)/(x+2)(x-3)=2x+6（(x-2-5）÷（x＋2）)÷（x-3）÷（2x 4） 化简