logaB-logaC=loga(B/C)log3(x+2)-log3(x^2-x-6)=log3[(x+2)/(x^2-x-6)]然后把1移到右边就是-1 -1=log3(1/3)所以就是log3[(x+2)/(x^2-x-6)] > log3(1/3)即：(x+2)/(x^2-x-6) > 1/3把三分之一移到不等号左边,化简：[(X...