求下列函数的二阶导数y=e^(x-1) y=In(x+√1+x^2)_数学解答

求下列函数的二阶导数y=e^(x-1) y=In(x+√1+x^2)

人气：411 ℃　时间：2019-08-18 00:22:29

解答

1)y'=e^(x - 1) y''=e^(x - 1)2)y'=(x/(x^2 + 1)^(1/2) + 1)/(x + (x^2 + 1)^(1/2))y''=(1/(x^2 + 1)^(1/2) - x^2/(x^2 + 1)^(3/2))/(x + (x^2 + 1)^(1/2)) - (x/(x^2 + 1)^(1/2) + 1)^2/(x + (x^2 + 1)^(1/2))^2