(x-3/3x^2-6x）/（x+2-5/x-2)={(x-3)/[3x(x-2)]}/{[(x+2)(x-2)-5]/(x-2)]}={(x-3)/[3x(x-2)]}/[(x²-9)/(x-2)]={(x-3)/[3x(x-2)]}/{[(x+3)(x-3)]/(x-2)]}=1/[3x(x+3)]=1/[3(x²+3x)]因为x是方程的根那么x
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