(24-根号2分子1)-2(根号8分子1+根号6) 怎样计算《要过程.
人气：472 ℃ 时间：2020-04-13 18:16:08
解答
首先√1/2=√2/2(二分之根号二),√1/8=√2/4(四分之根号二)
∴原式=(24-√2/2)-2(√2/4+√6)
=24-√2/2-√2/2-2√6
=24-√2-2√6
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