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数学
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(7m^2-4mn-n^2)-2(2m^2-mn+2n^2)计算.
人气:464 ℃ 时间:2020-02-03 16:03:53
解答
(7m^2-4mn-n^2)-2(2m^2-mn+2n^2)
=(7m^2-4m^2)-(4mn-2mn)-(n^2+4n^2)
=3m^2-2mn-5n^2
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