与向量a=(-6,8)垂直的单位向量坐标为
(8,6)。(-8,-6)为什么不可以
人气:392 ℃ 时间:2020-05-13 07:08:52
解答
设所求向量b=(x,y)
则:x^2+y^2=1
a⊥b,即:
a·b=(-6,8)·(x,y)=-6x+8y=0
即:3x=4y
故:(3x/4)^2+x^2=1
即:x^2=16/25
即:x=4/5或-4/5
即:y=3/5或-3/5
故:b=(4/5,3/5)或b=(-4/5,-3/5)
是2个答案,没问题的
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