> 数学 >
求不定积分∫x arctanxdx
人气:434 ℃ 时间:2020-09-16 07:50:37
解答
∫x arctanxdx
=1/2∫ arctanxdx^2
=x^2arctanx/2-1/2∫x^2darctanx
=x^2arctanx/2-1/2∫x^2/(1+x^2)dx
=x^2arctanx/2-1/2∫(1-1/(1+x^2))dx
=x^2arctanx/2-x/2+arctanx/2+C.
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版