如果方程组｛2x+3y=k-1；3x+2y=3k+1的解满足x>y,则k为多少? 2x+3y=k-1.(1)3x+2y=3k+1.(2)(2)-(1)得 x-y=2k+2,故有2x-2y=4k+4.(3)(1)-(3)得 5y=-3k-5,故y=-(3k+5)/5, x=y+2k+2=-(3k+5)/5+2k+2=(7k+5)/5因为x>y,...