[2x(x²y-xy²)+xy(2xy-x²)]
=2x³y-2x²y²+2x²y²-x³y
=x³y
因化简结果含有y,所以取值时需要y=条件2013,所以小辉说的是对的那如果是[2x(x²y-xy²)+xy(2xy-x²)]/(x²y)别的不变呢[2x(x²y-xy²)+xy(2xy-x²)]/(x²y)=(x³y)/(x²y)=x因为化简结果中不含y，所以求值时条件y=2013就是多余的。所以小明说的是对。