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3x/6x^2z a+b/a^2-b^2 x^2+2x+1/x^2+x 3x-6/x^2-4x+4
3x/6x^2z
a+b/a^2-b^2
x^2+2x+1/x^2+x
3x-6/x^2-4x+4
y-x/x^2-y^2
2x^2-10x/x^2-10x+25
约分:
3x/6x^2z
a+b/a^2-b^2
x^2+2x+1/x^2+x
3x-6/x^2-4x+4
y-x/x^2-y^2
2x^2-10x/x^2-10x+25
人气:256 ℃ 时间:2020-04-14 07:08:45
解答
3x/6x^2z =1/2xza+b/a^2-b^2=(a+b)/(a+b)(a-b)=1/(a-b)x^2+2x+1/x^2+x=(x+1)²/x(x+1)=(x+1)/x3x-6/x^2-4x+4=3(x-2)/(x-2)²=3/(x-2)y-x/x^2-y^2=-(x-y)/(x+y)(x-y)=-1/(x+y)2x^2-10x/x^2-10x+25=2x(x-5)/(x...
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